5x^2+100x-24000=0

Solution for 5x^2+100x-24000=0 equation:

5x^2+100x-24000=0

a = 5; b = 100; c = -24000;
Δ = b2-4ac
Δ = 1002-4·5·(-24000)
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{490000}=700$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-700}{2*5}=\frac{-800}{10}
=-80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+700}{2*5}=\frac{600}{10}
=60
$